Seward Lake

Seward Lake
Seward Lake is located in New York
Seward Lake
Seward Lake
Location of Seward Lake within New York State
LocationOtsego County, New York
Coordinates42°32′23″N 74°50′27″W / 42.53972°N 74.84083°W / 42.53972; -74.84083
Primary outflowsSchenevus Creek
Basin countriesUnited States
Surface area28 acres (11 ha)
Surface elevation1,237 ft (377 m)[1]
SettlementsSchenevus

Seward Lake is a small lake in Otsego County, New York. It is located west of Schenevus. Seward Lake drains west via an unnamed stream into Schenevus Creek.

References

  1. ^ "Hudson Lake". Geographic Names Information System. United States Geological Survey, United States Department of the Interior. Retrieved 2018-03-12.
This article is issued from Wikipedia. The text is available under Creative Commons Attribution-Share Alike 4.0 unless otherwise noted. Additional terms may apply for the media files.