1869 Iowa gubernatorial election|
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 County results Merrill: 50-60% 60-70% 70-80% 80-90% 90-100% Gillespie: 50-60% 60-70% No Data/Votes: |
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The 1869 Iowa gubernatorial election was held on October 12, 1869. Incumbent Republican Samuel Merrill defeated Democratic nominee George Gillespie with 62.93% of the vote.
General election
Candidates
- Samuel Merrill, Republican
- George Gillespie, Democratic
Results
References
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| Participants | Federal government | |
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State governments | |
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| Others | |
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| Elections | Presidential | |
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| U.S. Senate | |
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| U.S. House | |
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| Gubernatorial | |
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| U.S. elections | |
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| Key events | | Prelude | |
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| 1863 | |
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| 1864 | |
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| 1865 | |
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| 1866 | |
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| 1867 | |
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| 1868 | |
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| 1869 | |
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| 1870 | |
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| 1871 | |
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| 1872 | |
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| 1873 | |
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| 1874 | |
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| 1875 | |
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| 1876 | |
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| 1877 | |
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| Aftermath | |
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| Aspects | | Historiography | |
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| Memory | |
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| Legacy | |
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| Other topics | |
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