1890 Belgian general election|
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|      |  | First party | Second party |   |  | .jpg)  |   |   | Leader | Auguste Beernaert |  |   | Party | Catholic | Liberal |   | Leader's seat | Candidate for PM |  |   | Seats before | 98 seats | 40 seats |   | Seats won | 29 | 40 |   | Seats after | 94 | 44 |   | Seat change |  4 |  4 |   | Popular vote | 17,253 | 20,829 |   | Percentage | 45.15% | 54.51% |  | 
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 Partial general elections were held in Belgium on 10 June 1890.[1][2] In the elections for the Chamber of Representatives the result was a victory for the Catholic Party, which won 94 of the 138 seats.[2] 
Under the alternating system, elections were held in only four out of the nine provinces: Hainaut, Limburg, Liège and East Flanders. Thus, only 69 seats out of the 138 were up for election. Additionally, a special election was held in Neufchâteau on 3 June 1890.[3] 
  Results
 Chamber of Representatives
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| Party | Votes | % | Seats | 
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| Won | Total | +/– | 
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|  | Liberal Party | 20,829 | 54.51 | 40 | 44 | +4 | 
|  | Catholic Party | 17,253 | 45.15 | 29 | 94 | –4 | 
|  | Belgian Labour Party | 98 | 0.26 | 0 | 0 | New | 
|  | Others | 30 | 0.08 | 0 | 0 | 0 | 
| Total | 38,210 | 100.00 | 69 | 138 | 0 | 
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| Total votes | 38,210 | – |  | 
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| Registered voters/turnout | 59,452 | 64.27 |  | 
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| Source: Mackie & Rose,[4] Sternberger et al. | 
 Constituencies
 The distribution of seats among the electoral districts was as follows:[5] 
  References